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166
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Achieving the Space Elevator / Science & Technology / flying platform
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on: January 02, 2006, 09:28:43 PM
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The Smitherman paper is ridiculous for the simple fact that they (Smitherman is the editor of a NASA group report, I believe) sincerely propose constructing a 3,000 km tall tower, ignoring the fact that all LEO satellites would eventually crash into the thing. A thin ribbon that can be purposefully oscillated to avoid debris (as proposed by Edwards) is one thing; a thick, stationary tower that does nothing to deal with satellites is totally different, and a non-starter as far as I can tell. Absolutely correct! And it looks as if R&D is cheaper for Edwards' ribbon anyway. Go ribbon!
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167
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Achieving the Space Elevator / Science & Technology / Great, a ladder to space. But don't let go!
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on: January 02, 2006, 09:22:07 PM
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Be careful: there are 2 kinds of coriolis effects that are occuring on the SE. Ascension coriolis is the 'force' causing climber to move upwards faster as it approaches GEO. Rotational coriolis is the 'force' causing ribbon mass to lag westward as the Earth turns. I was speaking of rotational coriolis. Neither are actual forces, but really apparent movement changes due to a changing frame of perspective.
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168
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Achieving the Space Elevator / Science & Technology / Great, a ladder to space. But don't let go!
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on: January 02, 2006, 08:56:13 PM
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How could you possibly angle an SE either westward or eastward? If you're anchored at the equator, the counterweight is pulling it straight up with nothing to resist it moving to that position.
I don't know what you mean by "coriolis drift." Most people envision the SE as being at right angles where it is connected to the surface of the Earth at the base station. Angling the ribbon would involve moving the counterweight slightly to the east or slightly west of the base station. Actually, the counterweight would attempting to move east of the base at all times. The reason for this is that without the force of the counterweight, the ribbon would spiral dramatically westward as it lagged behind the earth's rotation. What keeps the ribbon straight and from not spiralling is the fact that it is connected to the counterweight. The counterweight is orbiting Earth above GEO with a 24 hour rotational period. Most satellites put in this position would immediately move into a higher, ellipictal orbit. The reason the counterweight does not move into a higher, ellipictal orbit is the fact that it is being held back by the ribbon. With the counterweight pulling up on the ribbon, the ribbon is also held taut. Since the Earth and the counterweight are both pulling the ribbon eastward at the ends, the ribbon actually spoons westward in the middle. By "coriolis drift" I meant the amount of spooning that occurs. Upon reflection, however, I am totally wrong. Neither tension nor spooning is necessarily dependant on the east-west movement of the counterweight. If the counterweight were to move eastward, it would also need to swing downward (moving into a lower and slower orbit but still with a 24 hour rotational period) in order to keep the same tension on the ribbon. Also, reeling the counterweight downwards would decrease the tension on the ribbon. This is why the required strength of the ribbon is dependant on the mass of the ribbon, and not the mass of the counterweight. Moving the counterweight westward would likely be impossible, since the counterweight is moving so fast for it's altitude it would immediatly swing back to the east. Perhaps it could be done temporarily with the pendulum method Temlakos describes. Things to consider: whiplash effect, reeling in/out the counterweight while angling, combining oscillations with angling, combining oscillations with pendulum movement, other satellite orbits. Be safe -Nydoc
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170
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Achieving the Space Elevator / Science & Technology / Weather, Lightning, Maintenance, other questions
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on: January 02, 2006, 01:04:04 AM
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Here are the direct quotes from the Edward's report : · Carbon nanotubes have a conductivity of 10^-4 milliohms. · The resistance of our cable (cross sectional area~2 mm^2) is 50kiloohms or greater from cloud to ground (does not account for epoxy). · Tethered balloons have been flown in thunderstorms and survived using Kevlar tethers. References to these programs have stated that the experiments were done when there was no rain. A wet tether or cable could change everything. Heating of the cable can be produced by passage through the local magnetic fields. The potential induced along the cable can be expressed as: E = B(r)v(r) where E is in volts/meter, B(r) is the magnetic field, and v(r) is the velocity of the cable relative to the magnetic field. For radii (r) <10rEarth, B(r) ~ 0.35_10^4rEarth^3/r^3 and v(r) is approximately zero. However, if we assume the worst possible case where the magnetic field is fixed and the cable is rotating with the Earth (v(r) = 463 r/rEarth m/s) we get potentials from 0.00026 V/m at 10rEarth to 0.016 V/m at Earth’s surface. At distances of greater than 10rE, the cable is in the interplanetary magnetic field during the day (Baverage ~6 nT and Bmax ~80 nT) and is in the Earth’s magnetosphere at night. This corresponds to a maximum potential of 0.00068 V/m at the far end of the cable. With a minimum resistance of 0.4 ohms/m we have a maximum of 0.0064 W/m of heating occurring near the Earth end of the cable and 1 muW at the far end. The cable would quickly radiate this level of heating away into space. The charge production rate in the ionosphere ranges between 2000 and 6000 q/cm3/s. For an area around the cable of 1km x 1km and 500km in vertical extent this relates to 1xE25 q/s or 625,000 C/s. With a resistivity 10^-4milliohms for carbon nanotubes, a 20-ton capacity cable (2 mm^2 cross section) would have a minimum resistance of roughly 5megaohms. For the cable to discharge the ionosphere at the same rate as charge is being produced would require a current of 625,000 Amps to flow through the cable. To produce this current a voltage difference of ~3E11 Volts would be required between Earth and the ionosphere. The measured electric field under thunderclouds just before a lightning strike is 10 – 20 kV/m. If we extend this electric field up to the ionosphere (which does not occur but should be a worst case) we find the static voltage potential would be less than 2E9 Volts. At this voltage difference with no redistribution of charge in the ionosphere we could discharge an area 100m around the cable. Since we have assumed the most conducting cable possible (in reality it would probably be down by orders of magnitude due the epoxy sections) and the highest potential difference conceivable it is more likely that only a small volume of centimeters radius would show any affect from the cable’s presence. And from Zhen Yao's paper: "Individual metallic nanotubes appear to be able to carry remarkably high current densities exceeding a gigaampere per square cm without breaking down."
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171
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Achieving the Space Elevator / Science & Technology / Great, a ladder to space. But don't let go!
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on: January 01, 2006, 11:25:40 PM
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"Small" propulsion system? That 23-degree orbital change I mentioned is no small deal--2 km/s delta-v, worst case. Let's hope that oscillations and transients will obviate that. Besides oscillations, another means of altering the escape trajectory would be angling the ribbon. Angled eastward, tension increases and coriolis drift decreases. Angled westward, coriolis drift increases and tension decreases. Of course, too much westward and the ribbon pulls the counterweight down. Also angling eastward is limited by the strength of the ribbon, which probably will be barely within margin.
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172
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Achieving the Space Elevator / Science & Technology / Materials: Geometry and Chemistry
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on: January 01, 2006, 10:33:55 PM
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I am mostly a space enthusiest so I do not know the number that will be needed to make it work. What is the strength that will be required for the final ribbon? It would certainly depend on the final width of the ribbon. I have heard estimates between 30GPa and 120GPa, but am unaware of a specific strength. Now for a picture of nanoyarn being spun!  Note that the individual threads are not continuous tubes. They are in fact many small pieces stuck together like wet noodles. The threads get pulled off the "wall" of the forest in an up-and-down fasion which is similar to that of a stack of folded printer paper being unfolded. This would have a lower GPa than the ideal continous tube.
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173
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Achieving the Space Elevator / Science & Technology / Building Upon the Seed Ribbon
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on: December 31, 2005, 02:33:27 PM
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Instead, could we just have the climbers reel out what is essentially a separate space elevator right beside the existing one? In this way we'd end up with a whole lot of ribbons beside each other and you wouldn't have the challenge of prestraining. Hmm. I'm not quite sure what you mean. In order for a climber to pull up a new thread, the initial thread would have to support the weight of the climber and the new thread. It would essentially be self-lifting at that point and therefore unnecessary. If you are talking about reeling a new thread down from GEO, that *is* possible. However, the whole point of combining threads is to save on rocket launches. It would be better to launch a thread that's twice as wide than 2 seperate ones.
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174
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Achieving the Space Elevator / Science & Technology / flying platform
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on: December 31, 2005, 12:25:55 PM
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The wording in section 2.6 is a bit tricky. I think you are correct in asserting that there is a practical height limit for a fractal truss. The actual height Smitherman gives is 3000 km, not 300 km. That kind of makes his claims a bit more suspicious. However, even a 1/4 mass reduction on the ribbon would mean savings on launch costs and maintance costs, so perhaps a smaller tower would be a good idea in conjunction with the elevator. I am trying to find a formula for ribbon mass as a function of tower height. The formula for the cable radius I have is x(y) = x exp{(d/2p)y[(gM/R(R+y))-w^2(R+(y/2))]} Where: M = 5.976*10^24 kg the Earth mass g = 6.6732*10^-11N m2/kg2 general gravitational constant w = 7.2921*10^-5 s^-1 the Earth angular speed R = 6.378*10^6m the Earth radius y the distance from the ground (altitude) d = 1.3*10^3 theoretical density of CNT p = 150*10^9 theoretical tensile strength of CNT To use your maximum 300km tower, R would instead equal 6.678*10^6. The value of y for GEO is 35.786*10^6. The equation should look something like this: x(y)= x exp{(1.3*10^3/2(150*10^9))3.5786*10^6[(6.6732*10^-11(7.35*10^22)/6.678*10^6(6.678*10^6+35.786*10^6))(-7.2921*10^-5)^2(6.678*10^6+(35.786*10^6/2))]} Unfortunately, the batteries on my calculator are dead. =( Would anyone care to check this? There should also be a slightly decreased tensile requirement on the ribbon as it is shorter with less gravity. Current plans for the SE have located it off the coast of South America, so a tower might need something like the Japanese megafloat. As long as waves are not a problem, you wouldn't have to worry about earthquakes either. If a suitable ribbon material cannot be found, then perhaps an electromagnetic launch rail would be the best bet for energy efficient space access. -Nydoc
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175
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Achieving the Space Elevator / Science & Technology / flying platform
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on: December 29, 2005, 03:21:27 PM
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Found the paper: here. Section 2.3 talks about the mass savings. Section 3.3.2 shows design of the tower. Smitherman also lists observation platforms, solar power recievers and LEO satellite replacement as potential uses of towers.
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176
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Achieving the Space Elevator / Science & Technology / flying platform
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on: December 29, 2005, 02:23:37 PM
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Since the tallest towers built so far are about one kilometers, 3000 kilometers would take centuries if we double the heigth each decade. It is prudent to add only about 10% to the previous tallest success. More than double would be total folly in the minds of most contractors. You are correct. This is another reason why I think a tower is non-feasible in the near future. However, there are no material limitations, so we may eventually consider building one in light of it's benefits. Can you explain 150 times? The tower may have 150 times the mass of the slightly shorter ribbon. You may be thinking taper backwards: the massive portion of the tether is near GEO altitude. Sure thing. The mass savings are not at the bottom of the ribbon, they are at the top. The the massive portion of the ribbon at GEO is necessary in order to support all of mass below it. Any given point below GEO has to support the mass below it as well. If the lowest point on the ribbon were to be elevated by 3000km, it would mean savings along the entire ribbon. The entire ribbon could be narrowed with 150 times less mass and still support the force necessary for a 20 ton payload. -Nydoc
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177
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Achieving the Space Elevator / Science & Technology / Another option...
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on: December 28, 2005, 11:24:43 PM
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I think that an arial platform would be non-feasible, given it's complexity. But as long as we're on the subject of non-feasible designs, I thougt I'd throw one out there. This is similar to the arial platform, but more along the lines of a 3000km high tower. Designs and PBO fibers required to build towers of this height do exist, only there is no current demand for towers of this height. The main benefit of building such a tower would be the reduction in mass required to build the elevator. Previously on this thread, that benefit has been called into question: Not so much. The bottom 10 km of the first SE will mass about 40 kg. That's about 0.005% of the total mass. Total savings, about 1,600 kg out of 800,000 kg. Not true! You forget that the width of the ribbon is exponentially related to it's length. I site the August 2000 NASA paper Space Elevators: An Advanced Earth-Space Infrastructure for the New Millennium by D.V. Smitherman, Jr. (sorry no link, I found it in the members only section of the yahoo groups SE site). In the paper, it was found that for materials of the same strength-to-density ratio, compression structures are less massive than tensile structures. The paper states that a 3000km tower with an attached GEO tether would be 150 TIMES less massive than a tensile-only structure! Other benefits of a tower include: - No wind requirements on the ribbon
- No lightning insulation requirements on the ribbon
- No required shielding of the ribbon from atomic oxygen
- Dramatically reduced chance of meteor collision on the ribbon (but not the tower)
- Lower cable loading on the ribbon, as cars will move faster with no atomospheric resistance
- The tower can be used for communications arrays
- The tower can be used for studies of the high atmoshpere
- The tower can be used to test long sections of ribbon and climbers
- The tower could be a tourist attraction
Additionally, when considering that the ribbon is required to have a high tensile-strength/density ratio, it's possible we could maintain the same volume while reducing the mass. With lowered density, the required tensile strength would be lowered as well. Perhaps even a self-lifting elevator would then be possible. The main problem with a tower is that it would collide with LEO satellites and space debri. That is why I say it is non-feasible. The tower idea may have to wait until tensile-only SEs can be used to clean up LEO and replace the satellites. Other problems are earthquakes (for land-based towers) and terrorist attacks. Do you think we could resolve this? -Nydoc
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178
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Achieving the Space Elevator / Education, Reference & Public Interest / Space Elevator in CIV4
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on: December 21, 2005, 02:03:59 PM
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Here's more pics. The first is a still from the animation where you see it built. Part of that includes a cut-away that shows a radial climbing mechanism and then it takes off pretty quick like a rocket. Not sure what the force shield effect is supposed to represent.. The second image is the world view. You can even zoom out and see the cable from space. 
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179
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Achieving the Space Elevator / Science & Technology / Weather, Lightning, Maintenance, other questions
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on: December 21, 2005, 11:11:02 AM
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Hi NYdoc: I was disapointed that few numbers were given, so I will have to guess. If the tether produces one million volts at one milliamp = one kilowatt, the climber may have some application for very high voltage dc. There are some mechanical methods for converting very high voltage at low current to low voltage at high current which would be good to charge batteries, power motors, and electronic gear. Unfortunately the converters are heavy, low efficiency and prone to failure. Neil After digging around, I found this article under the publications section of that site. It's about a different system called a MIXER. The MIXER has an input power level of 366kW and a current of 11.5 amps on the tether. It is built to withstands voltages in excess of 20kV. In order to work, however, that it rotates through Earth's magnetic field, so I don't think this kind of power generation is applicable to the SE, which is geostationary. I'm also given the understanding that formation of plasma along the tether is an issue, but I don't know if that would apply to the SE either. -Nydoc
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180
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Achieving the Space Elevator / Science & Technology / Weather, Lightning, Maintenance, other questions
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on: December 21, 2005, 09:18:18 AM
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These people are proposing that their tethers be used to remove most of the radiation in the Van Allen belts. While this would greatly reducing the shielding requirements for people using the SE I wonder if anyone has done a study of how reducing the belts would effect the weather or the amount of radiation reaching the surface of the Earth. The Van Allen Belts are 200km above the surface at closest points. The troposphere, stratosphere and mesosphere combined are only 80km thick. The belts do penetrate the thermosphere and the exosphere but over 99.9999% of our atmosphere is below their level. I highly doubt reducing the density of the belts would have any effect on the amount of radiation reaching earth. Considering the belts ARE radiation, removing them may even lower the amount of radiation we get. They don't provide a barrier either, since it is Earth's magnetosphere and the atmosphere which are shielding us from radiation. Some people even speculate that the radiation belts are not natural, but are a by-product of US or Russian nuclear testing.
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