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Author Topic: Falling house shelter  (Read 7087 times)
neil
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« on: April 05, 2007, 10:57:01 AM »

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Please check the assumptions and arithmetic. A multi-story house is held at the top of a square shaft 5 meters by 5 meters by 100 meters down into the Earth. Explosive bolts hold the house at the top of the shaft. The house is square, about 4.9 meters by 4.9 meters and 16 meters tall. When detectors on the roof detect photons from a nearby asteroid hit or H bomb explosion: The bolts blow, and the entire house begins to descend into the shaft at 16 meters per second per second. Since this is faster than gravity, very short burn rockets are needed on the roof to help push the house downward for 1/4 second. The house decends 1/2 meter and the loose items in the house, including the people are levitated to about 1/5 meter off the floor. Next the house descends at 9.5 meters per second = about 99% of the acelleration due to gravity, for 2 seconds. Lesser rockets will be needed to maintain this acceleration due to air resistance. The house descends 19 meters for a sub total descent of 19.5 meters. This means the house is clear of the top of the shaft, so the blast doors can finish closing about 1/10 th second later at t = 2.35 seconds. The loose stuff and people have returned to the floor. We next allow the people 1/10 th second to recover their balance at normal gravity, but the house is falling, so we need to hold the decent rate constant at about 23 meters per second to produce the sensation of not falling. The average acceleration for the first 2.25 seconds was about 12 meters per second per second so the speed of falling is 27 meters per second. From t= 2.25 to 2.35 the house falls 2.7 meters to a depth of 22.2 meters. We now need to decelerate the house to zero with respect to the bottom of the shaft. If we decelerate at 9 meters per second, per second, deceleration time is 3 seconds and the people experience almost twice normal gravity during the 3 seconds. The house decends another 40.5 meters during the last 3 seconds to t = 5.35 seconds and 62.9 meters down the shaft. We should likely think about 100 meters as a safety factor, to allow gradual transitions and the possibility that the blast wiil accelerate the house down the shaft if it arrives before the blast doors fully close, or the blast doors fail due to the blast.
Advantages are: Only 2.35 seconds warning of the blast are needed and the shelter is the house the famaly lives in. Disadvantages are the house is small and the shaft may cost more than a million dollars to construct. An extra room is needed at the bottom of the shaft for survival supplies and equipment. A sloping tunnel is needed to the surface when it is safe to return to the surface. As far as I know this is my idea, but a simular experirnce is enjoyed by guests of the Tower of Terror at MGM Studios which is one of 5 theme parks at Disney world, Florida, so the safety has been extensively analyzed. Neil
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« Reply #1 on: June 27, 2008, 05:23:27 AM »

Quote
shaft may cost more than a million dollars to construct.
I think that would be the main thing that will scare people away Wink
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« Reply #2 on: October 08, 2008, 05:35:04 AM »

I see no reason to construct that even for such big amount of money
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neil
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« Reply #3 on: October 15, 2008, 10:52:28 PM »

No reason? The falling house gives the occupants a shot at surviving certain death if the house remains on the surface during a nearby asteroid hit, or H bomb explosion.  Neil
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