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Power line inside the ribbon
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Author Topic: Power line inside the ribbon  (Read 13773 times)
Alistair Smith
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« on: May 24, 2007, 12:49:37 PM »

Hello all, I'm new to the forum.

I've spent many years thinking about a star ladder and I happen to think that in years to come, it will supercede rockets as the way people and mass is taken up into the skies above. It's great that I can express my views on a forum for other people to read who are also interested in seeing this project come to life.

I subscribe to the view that the star ladder will initially be laid out with a tiny, seed thread and will be reeled in by the counterweight and slowly reel in a thicker and stronger ribbon.

I say, that why not cash in on the potential a star-ladder has for powering the earth? Consider for a second a giant array of solar panels in orbit, harvesting electrical energy. Thousands of joules of solar energy are reflected back into space by the Earth's atmosphere.
In years to come, we are still going to have an energy crisis, nuclear, coal, oil and gas will be dwindling as we fight for control of what little fossel fuels remain on this planet. Meanwhile, the sun will still be shining for billions of years.

If during the construction of the ribbon, you could reel up a power line made out of a special nano-tech material designed for electrical conductivity whilst still being lightweight and super-strong, you could do three things:

1. Provide people on Earth with free electrical energy.
2. Power the climber via Electromagnetic induction from the power line inside the ribbon.
3. Gain funding from environmental groups to help begin the construction of the star ladder.

Why should the star ladder be purely about bringing people and mass to and from space? Why not energy as well....

Those are my thought, I would really appreciate any feedback anyone has to say about the matter.

Thanks those for taking the time to read my post.

Kind Regards,

Alistair Smith
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Merlynx
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« Reply #1 on: May 25, 2007, 06:14:34 AM »

Welcome.

Not to be too much of a wet blanket (I'll leave that to the old hands), but a few problems arise.

Unless you are using a superconductor, electrical resistance over the distances involved becomes prohibitive.
Every extra gram of weight causes a great deal of stress on the structure, meaning that unless the power cable is an integral structural element, it would probably add too much to the cost to carry that extra mass

Although, now that I think about it, the high-temperature superconductors are getting better, perhaps if the ribbon radiates enough incident energy back into space, the majority of the ribbon could be maintained in a super-conducting state without additional cooling apparatus.
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Merlynx
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A_M_Swallow
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« Reply #2 on: May 25, 2007, 11:26:37 AM »

As an alternative to winching electrifying the first say 300 km of the ribbon is probably worth while.  This would power the lifter through the atmosphere.  After that the solar panels can be opened in a vacuum.  The ribbon would need splitting into two and coating with an insulator.  The coating may also protect the ribbon against oxygen.

Electrifying the cable up to 1000 km would reduce the mass of photovoltaic cells by a quarter.  The same quantity of cooling is still needed.


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Andrew Swallow
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« Reply #3 on: May 25, 2007, 02:06:11 PM »

Calculating the resistance of the cable.

From http://en.wikipedia.org/wiki/Electrical_resistivity

“The electrical resistivity ρ (rho) of a material is given by
For a height of 300 km = 300,000 m

R300 = 1 e-4 * (2 * 300,000) / 1 e-6 = 60,000,000 = 60 mega-ohms

For a height of 1000 km = 1 e 6 m


         ρ = R A / l

where
ρ is the static resistivity (measured in ohm metres, Ωm);
R is the electrical resistance of a uniform specimen of the material (measured in ohms, Ω);
l is the length of the specimen (measured in metres, m);
A is the cross-sectional area of the specimen (measured in square metres, m²).

Electrical circuits need both a wire from the generator to the motor and a return wire.  The ribbon would have to be split into two to provide the pathways.

At the Earth's surface cross section area of the ribbon is 2 mm^2
If split in two, for power up and power down, the cross section are becomes 2/2 = 1 mm^2 = 1 e-6 m^2


ρ = R A / l  can be re-arranged to   R = ρ l / A

ρ for CNT =  10-4 Wm (or 1 e-4)


For a height of 200 km = 200,000 m

R300 = 1 e-4 * (2 * 200,000) / 1 e-6 = 40,000,000 = 40 mega-ohms


For a height of 300 km = 300,000 m

R300 = 1 e-4 * (2 * 300,000) / 1 e-6 = 60,000,000 = 60 mega-ohms


For a height of 1000 km = 1 e 6 m

R1000 = 1 e-4 * (2 * 1 e 6) / 1 e-6 = 200,000,000 = 200 mega-ohms

Note:  1 mm^2 is the thickness of a cotton thread.  Long distance electrical cables are normally several inches thick.



Edit to add resistance to 200 km
« Last Edit: May 30, 2007, 06:12:05 PM by A_M_Swallow » Logged

Andrew Swallow
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« Reply #4 on: May 28, 2007, 11:39:35 AM »

Where:
P = Power in Watts
I = Current in Amps
V = Potential difference in Volts
R = Resistance in Ohms

P = I V

P = I2 R

P = V2 / R


Although trains are normally powered by 600 V dc (direct current) and power transmission lines work as 110 kV ac (alternating current) the resistances are so high that I am using the extra high voltage of 1200 kV ac.
http://en.wikipedia.org/wiki/Electric_power_transmission
http://en.wikipedia.org/wiki/High_Voltage

At a height of 200 km the resistance is 40 mega-ohms

P = V2 / R = 1.2 e 6 ^2 / 4 e 7 = 36,000 Watts = 36 kW

At s height of 1000 km the resistance is 200 mega-ohms.

P = 1.2 e 6 ^ 2 / 2 e 8 = 7,200 Watts = 7.2 kW

Unfortunately the climbers need mega-Watts.  To be usable voltages 100 times larger or resistances 100 times smaller or a mixture.  Depending on how the cables are made the resistance used in these calculations may be too high.
« Last Edit: May 28, 2007, 11:52:37 AM by A_M_Swallow » Logged

Andrew Swallow
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« Reply #5 on: May 28, 2007, 12:17:55 PM »

Turning this around, how fast would a climber at 300 km be if powered from the ground?

Work W = F * delta_s
where delta_s is the distance per second or velocity

W = m gh v

v = W / (m gh)

Now W = Power P * efficiency

P = V2 / Rh

v = (V2 / Rh) * efficiency / (m gh)
giving
v = (V2  * efficiency) / (Rh * m * gh)

Using an efficiency of 30%, a height of 300 km and a mass of 25 tonne
R300 km = 60 mega-ohms
g300 km = 8.94 m/s/s

v = ( 1.2 e 6 ^ 2 * 0.3) / (6 e 7 * 25,000 * 8.94)
= 0.0322 m/s  (0.116 km/h)

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Andrew Swallow
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« Reply #6 on: May 30, 2007, 06:27:30 PM »

There is a plan to use ribbon that is 1 cm in width below 10 km, taking that up to 200 km.

1 cm diamter = 0.01 m = 0.005 m radius
A = pi r2 = pi * 0.005 * 0.005 = 7.85 e-5 m^2

If split in two, for power up and power down, the cross section are becomes 7.85 e-5/2 = 3.93 e-5 m^2


ρ = R A / l  can be re-arranged to   R = ρ l / A

ρ for CNT =  10-4 Wm (or 1 e-4)


For a height of 200 km = 200,000 m

R300 = 1 e-4 * (2 * 200,000) / 3.93 e-5 = 10,200,000 =  10.2 mega-ohms

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Andrew Swallow
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« Reply #7 on: May 31, 2007, 11:53:02 AM »

You don't actually need 2 sepearate cables to transmit power, a single cable can transmit an AC signal (allowing inductive power transfer) without a return wire, provided the cable has a sufficient capacitor at each end.
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Merlynx
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« Reply #8 on: May 31, 2007, 06:41:26 PM »

I recall a single wire transmission line for radio frequencies. IIRC = If I recall correctly the efficiency was good for a few meters. Any chance efficiency is good for thousands of kilometers? A capacitor can not be avoided at the far end, but the Q is very poor as the other side of the capacitor has to find its way though space and Earth's atmosphere. Have you more details?   Neil
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windemut
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« Reply #9 on: June 01, 2007, 09:40:14 PM »

I recall a single wire transmission line for radio frequencies. IIRC = If I recall correctly the efficiency was good for a few meters. Any chance efficiency is good for thousands of kilometers? A capacitor can not be avoided at the far end, but the Q is very poor as the other side of the capacitor has to find its way though space and Earth's atmosphere. Have you more details?   Neil
I think what is meant is a Goubau line (http://en.wikipedia.org/wiki/Single-wire_transmission_line). AFAIK it is not competitive with conventional power transmission lines, and would not be suitable for powering the SE. I have also seen calculations once where it was proposed to use the SE as a waveguide for microwave power transmission. It turned out that losses would be too great. I think a non-hollow waveguide and a Goubau line are really the same thing.

Andreas
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John O'Halloran
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« Reply #10 on: June 06, 2007, 06:53:47 PM »

I do not think the ribbon will be able to be used for trasmitting power back to earth untill a room temperture super conductor that has much the same characteristic of carbon nanotubes is developed.

For powering the climber at the start of its run seems like it would be quite easy. I think running it out to 1000 km might be difficult but 100 km or so might be possible. This would get it above almost all of the atmosphere. A conducting strip on either edge of the ribbon would provide a sort of third rail and a complete circuit while the climber is on the ribbon.
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A_M_Swallow
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« Reply #11 on: June 07, 2007, 12:55:23 AM »

For powering the climber at the start of its run seems like it would be quite easy. I think running it out to 1000 km might be difficult but 100 km or so might be possible. This would get it above almost all of the atmosphere. A conducting strip on either edge of the ribbon would provide a sort of third rail and a complete circuit while the climber is on the ribbon.
The 100 km strips will need to have a round trip resistance of less than 5 M-ohms whilst being extremely light in mass.  Every ounce is an ounce off the payload.

Alternatively the LiftPort ship could have a 100 km tall poll that a truck uses to lift the main climbers.  The poll would have to be made out of something like artificial diamond.

Balloons and extra cables from balloons can be used to lift the climbers to about 30 km.  Depending on the wind the climbers may be able to use their own rollers and solar panels above that.
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Andrew Swallow
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« Reply #12 on: June 07, 2007, 06:48:19 PM »

http://www.physorg.com/preview100445957.html

Seems to me such wireless transfer of energy would in large part alleviate both the weight of the "transmission lines" and associated problems with resistance.  Further, no physical connection is then required between the ribbon and lifter, so friction and drag should be greatly reduced, if not eliminated from such a connection.

While not a scientist or engineer as many of you appear to be, from a logic stance, it would seem that using a magnetic propulsion system to power the lifter would be one of the "best options".  We already have the technology and experience building such systems.  Such a system would not have to use "rollers or other mechanical attachement to the ribbon", which would mean less friction, wear and tear, and chance to damage the ribbon from such a mechanical form of locomotion. 

As A.M. Swallow already posted in the precurser section:

http://www.newscientisttech.com/channel/tech/mg19125686.300-rusty-rind-adds-magnetic-allure-to-nanotubes.html

It appears both feasible and likely that by the time the nanotube ribbon material is likely to be available in such quantities and length to start building the ribbon, that making such nanotubes magnetic should be also well developed. 

Taken together, the wireless transfer of energy, and magnetic propulsion would give us an extremely efficient and lightweight alternative to both power and give locomotion to the climbers. This system would also resolve some of the questions about how to place/power navigational beacons on the ribbon, the concern of atmospheric drag on lifter based solar panels, and provide a simple method for providing power to the life support needs of the lifter without added weight of batteries, engines or other options that have been discussed.

As an added bonus, the high efficiency and low friction of the magnetic propulsion system can create a very high rate of speed and accelleration over distance, that might well be able to shorten the currently accepted, 7 day trip estimate. 

This approach also adds another future capability to the space elevator.  While a standard lifter would be accellerated and then decellerated by the magnetic propulsion system to allow for a safe and easy docking at the top of the elevator, this same "ribbon" and propulsion system could continue to accellerate specially designed "lifters" that would instead use the speed and inertia gained from the lifting system to "launch" from the ribbon as self contained space ships.  Such a system would likely be the cheapest and most efficeient model for supplying/cargo hauling to both the moon and mars.
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A_M_Swallow
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« Reply #13 on: June 11, 2007, 01:23:18 AM »

Power transmission requires the climber to have a big aerial to receive the power.  This will have a large atmospheric drag, holes will reduce the drag but it is still big.

A 1% increase in ribbon mass due to the use of magnetic materials is 1% * 1500 tonne = 15 tonne
This is more than half the weight of a climber.  So either lighter climbers will have to be used or a thicker cable will have to be used.
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Andrew Swallow
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« Reply #14 on: June 14, 2007, 06:18:45 PM »

Balloons and extra cables from balloons can be used to lift the climbers to about 30 km.  Depending on the wind the climbers may be able to use their own rollers and solar panels above that.

I think the balloon assist is a very clever idea. I do not know how easy it would be to put into practice but it would allow for a number of possibilities. More climber could be on the ribbon at any one time since the load at the location of the highest gavity would be reduced. It would be a way to increase the maximum load the elevator could carry for the same reason. It could provide an additional safety feature for the elevator durring the period that a failure to the climber or the ribbon could be most dangerous to the cargo.
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