Calculating the resistance of the cable.
From
http://en.wikipedia.org/wiki/Electrical_resistivity“The electrical resistivity ρ (rho) of a material is given by
For a height of 300 km = 300,000 m
R
300 = 1 e-4 * (2 * 300,000) / 1 e-6 = 60,000,000 = 60 mega-ohms
For a height of 1000 km = 1 e 6 m
ρ = R A / l
where
ρ is the static resistivity (measured in ohm metres, Ωm);
R is the electrical resistance of a uniform specimen of the material (measured in ohms, Ω);
l is the length of the specimen (measured in metres, m);
A is the cross-sectional area of the specimen (measured in square metres, m²).
Electrical circuits need both a wire from the generator to the motor and a return wire. The ribbon would have to be split into two to provide the pathways.
At the Earth's surface cross section area of the ribbon is 2 mm^2
If split in two, for power up and power down, the cross section are becomes 2/2 = 1 mm^2 = 1 e-6 m^2
ρ = R A / l can be re-arranged to R = ρ l / A
ρ for CNT = 10
-4 Wm (or 1 e-4)
For a height of 200 km = 200,000 m
R
300 = 1 e-4 * (2 * 200,000) / 1 e-6 = 40,000,000 = 40 mega-ohms
For a height of 300 km = 300,000 m
R
300 = 1 e-4 * (2 * 300,000) / 1 e-6 = 60,000,000 = 60 mega-ohms
For a height of 1000 km = 1 e 6 m
R
1000 = 1 e-4 * (2 * 1 e 6) / 1 e-6 = 200,000,000 = 200 mega-ohms
Note: 1 mm^2 is the thickness of a cotton thread. Long distance electrical cables are normally several inches thick.
Edit to add resistance to 200 km